The total x: 5-3=2

The total y: 3-7=-4

So let the starting point be (0,0), then the finish point would be (2,-4). If we imagine the way as a right triangle, the straight-line distance would be the hypothenuse. Use the Pythagorean Theorem:

\(\displaystyle{d}^{{2}}={2}^{{2}}+{\left(-{4}\right)}^{{2}}\)

\(\displaystyle{d}=\sqrt{{{4}+{16}}}\)

\(\displaystyle{d}=\sqrt{{20}}\)

Calculate:

\(\displaystyle{d}\approx{4.47}\)

The straight-line distance would be approximately 4.47 blocks.